# What Happens to a Ball's Energy When Thrown Upwards?

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• rudransh verma
In summary, the force of the throw is doing work for distance d, and the force of gravity is doing work for distance s.
rudransh verma
Gold Member
What is going on when the ball is thrown up in the sky. It is pushed by a force F for some distance d. Then the object travels a distance s up in the sky before finally coming to a stop. So what is going on here? Is the force doing work for distance d or distance s (s>d)?
I think change in kinetic energy is due to a force. So even when the momentary push is done the force is still acting all the way to the top and the work done by the force is for distance d. Right?

Lnewqban
Person does work ##w_1 = Fd##, weight does work ##w_2 = -mg(d+s)##, and ##w_1 + w_2 = 0## for the ball comes to rest at the highest point.

russ_watters
ergospherical said:
Person does work ##w_1 = Fd##, weight does work ##w_2 = -mg(d+s)##, and ##w_1 + w_2 = 0## for the ball comes to rest at the highest point.
Why not ##w_1=F(d+s)##? Force is also doing work for s distance.

rudransh verma said:
Why not ##w_1=F(d+s)##? Force is also doing work for s distance.
Not really, because force of person stops once it leaves their hands.

ergospherical said:
Not really, because force of person stops once it leaves their hands.
But pushing the ball up is changing its kinetic energy.

Muscles-hand doing work for distance d only.
That means that the ball is gaining energy only during that time in form of impulse.
For distance s, the ball has momentum, which is how that previously gained energy manifests itself.

https://en.m.wikipedia.org/wiki/Impulse_(physics)

:)

Lnewqban said:
Muscles-hand doing work for distance d only.
That means that the ball is gaining energy only during that time in form of impulse.
I don’t understand. Why is the s distance situation different from d distance situation?

rudransh verma said:
I don’t understand. Why is the s distance situation different from d distance situation?
What is the definition of a force?

https://en.m.wikipedia.org/wiki/Force

:)

Lnewqban said:
What is the definition of a force?

https://en.m.wikipedia.org/wiki/Force

:)
Push or pull which causes acceleration.
Force is applied by the hand because we are changing the momentum in some time. Force is also acting on the body when it leaves the hand. So?

Last edited:
rudransh verma said:
Push or pull which causes acceleration
Why?

Is the ball increasing its velocity after losing contact with the hand?

You could use work-energy theorem to calculate and resolve this.
rudransh verma said:
Push or pull which causes acceleration.
Force is applied by the hand because we are changing the momentum in some time. Force is also acting on the body when it leaves the hand. So?
Clearly the force is no longer acting on the ball when it leaves the hand. Why are you saying it still is?

You know, you could use work-energy to calculate all this, right?

Lnewqban said:
Is the ball increasing its velocity after losing contact with the hand?
So the ball starts deaccelerating as soon as it leaves the hand since net force is downwards.
Lnewqban said:
Muscles-hand doing work for distance d only.
That means that the ball is gaining energy only during that time in form of impulse.
For distance s, the ball has momentum, which is how that previously gained energy manifests itself.
First we do work for distance d increase its KE and increase its momentum then as soon as it leaves the gravity does opposite work and decrease its kinetic energy and momentum again to zero. If there were no gravity the body would cruise as soon as it would leave the hand with constant momentum and kinetic energy.

ergospherical and Lnewqban
rudransh verma said:
So the ball starts deaccelerating as soon as it leaves the hand since net force is downwards.

First we do work for distance d increase its KE and increase its momentum then as soon as it leaves the gravity does opposite work and decrease its kinetic energy and momentum again to zero. If there were no gravity the body would cruise as soon as it would leave the hand with constant momentum and kinetic energy.
Excellent!

:)

Last edited:
rudransh verma
rudransh verma said:
What is going on when the ball is thrown up in the sky. It is pushed by a force F for some distance d. Then the object travels a distance s up in the sky before finally coming to a stop. So what is going on here? Is the force doing work for distance d or distance s (s>d)?
There are two forces involved here. The force of the throw pushes the ball upward for some distance d. The force of gravity pulls the ball downward over some distance s. This is all very straightforward. What's the problem?

jim mcnamara and russ_watters

## What causes the ball to go up when it is thrown?

The ball goes up due to the force of the throw and the force of gravity pulling it downwards.

## Why does the ball eventually come back down?

The force of gravity is constantly acting on the ball, pulling it back towards the ground.

## What factors affect how high the ball will go?

The initial force of the throw, the angle at which the ball is thrown, and any external forces such as air resistance can affect how high the ball will go.

## Can a ball be thrown up without it coming back down?

No, the force of gravity will always pull the ball back towards the ground.

## How does air resistance impact the trajectory of a thrown ball?

Air resistance can slow down the ball and change its trajectory, making it fall at a different angle or distance than it would without air resistance.

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