What is the acceleration experienced by the puck?

In summary, the conversation discusses a question about a hockey puck's acceleration on ice. The individual initially calculates an incorrect answer using the formula vf-vi/tf-ti and realizes their mistake when considering the initial velocity. Another individual suggests using the equation v^2=vo^2+2a(x-xo) and the first individual eventually arrives at the correct answer of -1.01m/s^2. The conversation ends with appreciation for the helpful explanation.
  • #1
petal5
26
0
I've been attempting the following question:

A 120gram hockey puck sent sliding over ice with an initial speed of 5.5m/s is stopped in 15m by the frictional force on it from the ice.What is the acceleration experienced by the puck?

I'm getting an answer of 2.0157m/s^2.I'm wondering if this is correct or not?
Thanks.
 
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  • #2
If you assume the acceleration is constant then your answer is incorrect. Perhaps if you show your working we could correct you. Also note that the acceleration should be negative since the puck's velocity is decreasing.
 
  • #3
i used the formula vf-vi/tf-ti to get that answer
 
  • #4
petal5 said:
i used the formula vf-vi/tf-ti to get that answer
And how did you calculate the time?
 
  • #5
i divided 15m by 5.5m.however,i now realize this is wrong as the 5.5m. is INITIAL speed
 
  • #6
petal5 said:
i divided 15m by 5.5m.however,i now realize this is wrong as the 5.5m. is INITIAL speed
Indeed, so if we assume the acceleration to be uniform how does the displacement, initial and final velocity relate to the acceleration?
 
  • #7
sorry,i've no idea.
 
  • #9
would it be this equation:v^2=vo^2+2a(x-xo)
 
  • #10
petal5 said:
would it be this equation:v^2=vo^2+2a(x-xo)
Indeed it would, all that is left to do is some algebraic manipulation and to substitute in your values.
 
  • #11
thanks for all your help.i'm now getting -1.01m/s^2
 
  • #12
petal5 said:
thanks for all your help.i'm now getting -1.01m/s^2
Looks about right to me. My pleasure.
 
  • #13
Thanks so much,you're a great teacher!
 
  • #14
petal5 said:
Thanks so much,you're a great teacher!
Thank you very much :smile: I do my best.
 

Related to What is the acceleration experienced by the puck?

1. What is acceleration?

Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning it has both magnitude and direction.

2. How is acceleration calculated?

Acceleration is calculated by dividing the change in velocity by the change in time. The formula for acceleration is a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

3. What factors affect the acceleration of a puck?

The acceleration of a puck can be affected by the force applied to it, its mass, and any resistance or friction it encounters.

4. What units are used to measure acceleration?

Acceleration is typically measured in meters per second squared (m/s^2) in the metric system or feet per second squared (ft/s^2) in the imperial system.

5. How does acceleration relate to Newton's Second Law of Motion?

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that the greater the force applied to a puck, the greater its acceleration will be, and the more massive the puck is, the less it will accelerate for a given force.

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