What is the angle that maximizes R?

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Homework Help Overview

The problem involves finding the angle that maximizes the distance R traveled by an object projected up an inclined plane, given a specific equation that relates R to the angle theta. The context is within the subject area of projectile motion and trigonometry.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the transformation of the equation using trigonometric identities, particularly focusing on sin(2x) and cos(2x). There is an exploration of how to manipulate the original equation to facilitate solving for theta.

Discussion Status

The discussion is ongoing, with participants providing insights into trigonometric identities and their application to the problem. There is no explicit consensus yet, but some guidance on rewriting the equation in terms of these identities has been offered.

Contextual Notes

Participants are navigating through the complexities of the equation, particularly the presence of multiple trigonometric identities and their implications for solving the problem. There is an acknowledgment of the need to simplify the equation further.

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Homework Statement



Sorry for the long intro:

An object is propelled up at angle theta 45 deg. < theta < 90 deg. to the horiz. with initial vel. of V0 m/s. from the base of a plane that makes an angle of 45 deg. with the horiz.
If air resistance is ingored, the distance, R, traveled by the object up the inclined plane, is
R = V^2(sqrt 2)/ 32 (2sinthetacostheta - 2cos^2theta

Question
You are asked to find the angle that maximizes R by solving equation
2sinthetacostheta + 1 - 2sin^2theta = 0
Solve for theta.

Homework Equations


Not really any equations, just solving.

The Attempt at a Solution


I tried to continue with this, but I don't know what to do when there are two different identities.

Would I factor?
 
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Do you know what sin(2x) and cos(2x) equal in terms of cosx and sinx?
 
Mentallic said:
Do you know what sin(2x) and cos(2x) equal in terms of cosx and sinx?


Well, sin(2x) = 2sinxcosx
and cos(2x) = 2cos^x - sin^2x or 2cos^2x - 1 or 1- 2sin^2x
Is that what you mean?
 
Yes, so do you see how you can change your equation in terms of sin(2x) and cos(2x)?

Now how would you go about solving something like sin(2x)=cos(2x)
You don't need to worry about the 2x for the moment, you can just think of it as any other variable angle.
 

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