What is the angular displacement of a thrown ball

AI Thread Summary
The discussion revolves around calculating the angular displacement of a ball thrown to a man, with a specified angular velocity of 330 revolutions per minute and a time of 60 seconds for the throw. The initial conversion of angular velocity to radians per second was incorrect, as the user mistakenly used π instead of 2π, leading to confusion in the calculations. After realizing the error, the user considered adjusting the time to 0.60 seconds to match one of the provided answer options. The conversation highlights the importance of accurate unit conversion and normalization of angular displacement. Ultimately, the key takeaway is the need for precise calculations to arrive at the correct angular displacement.
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Homework Statement


A ball is thrown to a man and reaches him in 60s. The ball curves because it is spinning at an average angular velocity of 330 rev/min on its way to the man's hands. What is the angular displacement of the ball


Homework Equations


θ=ωt

The Attempt at a Solution


I converted 330 rev/min to 17.279 rad/s
but when I plug it into the equation I get 1,036.74... I feel like I'm missing a final step here but I don't know what I'm doing wrong.. please help
 
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Hello, ashezb. Welcome to PF!

Are you sure the time is 60s? That's one heck of a throwing arm :bugeye:

Your conversion of 330 rev/min to rad/s does not look correct. Remember, there are ##2\pi## radians in one revolution.
 
ashezb said:

Homework Statement


A ball is thrown to a man and reaches him in 60s. The ball curves because it is spinning at an average angular velocity of 330 rev/min on its way to the man's hands. What is the angular displacement of the ball


Homework Equations


θ=ωt

The Attempt at a Solution


I converted 330 rev/min to 17.279 rad/s
but when I plug it into the equation I get 1,036.74... I feel like I'm missing a final step here but I don't know what I'm doing wrong.. please help
Hi ashezb, Welcome to Physics Forums.

How did you convert 330 rpm to radians per second? Can you write it out? (I ask because your value doesn't look right).

Once you have the total angular distance, remember that the displacement should lie in the range 0 → ##2\pi##. How might you go about reducing (normalizing) the angle?
 
Now that I really think about it 60s is one heck of a throw, but the question does say 60s

Yes I did my conversion wrong. I used π in stead of 2π

but I am still confused...these are the given answers
a) 21 rad
b) 20 rad
c) 19 rad
d) 17 rad
e) 14 rad

The only way I can make is work is to turn the seconds into 0.60 seconds in which case a would be correct.

Thanx for being so welcoming and so helpful :)
 
ashezb said:
The only way I can make is work is to turn the seconds into 0.60 seconds in which case a would be correct.
Sounds good.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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