What is the angular momentum of an electron

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SUMMARY

The angular momentum of an electron in the Bohr model is quantized and given by the formula L = nħ, where ħ (h-bar) is Planck's constant divided by 2π. For an electron in the n = 13 energy level, the angular momentum can be calculated using this formula. The radius of the electron's orbit is determined by r = n²a, where a = 5.29 x 10-11 m. It is important to note that an electron in an s state can have zero angular momentum despite being in a higher energy level.

PREREQUISITES
  • Understanding of the Bohr model of the hydrogen atom
  • Familiarity with Planck's constant (h = 6.63 x 10-34 J s)
  • Knowledge of angular momentum concepts (L = r x p)
  • Basic grasp of quantum mechanics and electron states
NEXT STEPS
  • Research the derivation of the angular momentum formula L = nħ in quantum mechanics
  • Study the implications of electron states (s, p, d) on angular momentum
  • Learn about the differences between classical and quantum angular momentum
  • Explore the significance of quantization in atomic models
USEFUL FOR

Students of physics, particularly those studying quantum mechanics, and educators explaining the Bohr model and angular momentum concepts.

pooka
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What is the angular momentum of an electron in a level with n = 13 in the Bohr hydrogen atom (Planck's constant: h = 6.63 10-34 J s)?

I used the equation L= mr2ω
L=nh/2pi

I solved for r:
r = n2a where a=5.29•10-11 m

plugging all these values in, i can't seem to get the right answer for angular momentum. Also what are the units for angular momentum?
 
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Gack! Angular momentum is r x p. r is meters, p is kg*m/sec. But an electron can be in level n=13 with zero angular momentum if it's in an s state. I don't get the question.
 
Last edited:
He said bohr model, and in that model you don't have s,p,d waves etc.

but instead, L is quantized as: L = n*hbar

So that is basically what you need dude
 

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