# What is the angular speed in revolution per minute?

## Homework Statement

You are consulting for an amusement park that wants to build a new "Rotor" ride. In order to increase capacity, they would like to build a unit with a 14.2-ft diameter. The Rotor should provide a centripetal acceleration of 3g. What must be the angular speed in revolutions per minute (rpm)?

v=ωr

## The Attempt at a Solution

1ft=0.3048m---> 14.2ft*0.3048m/ft= 4.33m

3(9.81m/s^2)= 29.43m/s^2

v^2=2.16*29.43m/s^2=63.5688

sqrtv=sqrt63.5688=7.97m/s

v=ωr
7.97m/s=ω2.16

7.97/2.16=ω

344.77rpm is my final answer but I got that wrong, where did I go wrong in my calculations?

It seems like you are taking the correct steps. However, I get a different numerical answer than you do.

Also, may I suggest that you don't plug all of those numbers in immediately, and just work with symbols until you have an expression for what it is you are looking for? It'll make the work easier for you, and you'll be less error prone.

Chestermiller
Mentor
It's correct up to the very last step. Then, you got the decimal point in the wrong place.

Chet

yeah I realize that. it seems that I have to convert rad/s to rpm