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## Homework Statement

You are consulting for an amusement park that wants to build a new "Rotor" ride. In order to increase capacity, they would like to build a unit with a 14.2-ft diameter. The Rotor should provide a centripetal acceleration of 3g. What must be the angular speed in revolutions per minute (rpm)?

## Homework Equations

a(centripedal)= v^2/radius

v=ωr

## The Attempt at a Solution

1ft=0.3048m---> 14.2ft*0.3048m/ft= 4.33m

4.33/2= 2.16(this is the radius)

3(9.81m/s^2)= 29.43m/s^2

v^2=2.16*29.43m/s^2=63.5688

sqrtv=sqrt63.5688=7.97m/s

v=ωr

7.97m/s=ω2.16

7.97/2.16=ω

ω=3.69rad/s

3.69rad/s*1rev/2∏*60s/1m= 344.77rpm

344.77rpm is my final answer but I got that wrong, where did I go wrong in my calculations?