. What is the antiderivative of e^arctan(x)?

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Homework Help Overview

The discussion revolves around finding the antiderivative of the function e^arctan(x), which is part of a calculus assignment. The original poster expresses difficulty in identifying the antiderivative, suggesting it should be straightforward based on prior knowledge from Calculus 1.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the transformation of the integral into a different form involving tan(u) and e^u, questioning the validity of substitutions made. There is also mention of integration by parts and the realization that the problem might be a trick question.

Discussion Status

Some participants have provided insights regarding the nature of the integral and its relation to elementary functions. There is acknowledgment that certain functions, like the one in question, do not have "nice" antiderivatives. The conversation reflects an ongoing exploration of the topic without reaching a definitive conclusion.

Contextual Notes

The original poster notes that the problem was intended to be a review but turned out to be more complex than anticipated. There is also a mention of a misunderstanding regarding the integral sign in the problem statement.

silverdiesel
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What is the antiderivative of earctan(x)?
I can't seen to find this anywhere, although I suspect the answer would be pretty easy. This is the first problem of the first assignment in Calc 2. It is suposed to be review from Calc 1, but I can't figure it out. :cry:
 
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You can turn that into the integral of tan(u) eu, which doesn't have an integral expressible in terms of elementary functions, and so neither does your original function. Now if that was arcsin or arccos in the exponent, it'd be a different story.
 
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StatusX said:
You can turn that into the integral of tan(u) eu, which doesn't have an integral expressible in terms of elementary functions, and so neither does your original function. Now if that was arcsin or arccos in the exponent, it'd be a different story.

You're subvstitution is wrong, it would work if he had xearctan(x) but you set u = arctan(x) which means x = tan(u) but there is no multiplication between x and e in his problem so you can get tan(u) eu, but you could get sec2u eudu.
 
Right, and then I integrated by parts.
 
StatusX said:
Right, and then I integrated by parts.

Ah, yeah I see that now sorry about that.
 
Thanks for your help. I did finally figure out the problem. It was a trick question, and I was not supposed to be able to figure out the antiderivitave. The whole problem was this:

d/dx(S01earctan x)dx

that "S" is supposed to be an integral sign.


I eventually figured.. The integral of earctan x, however you figure it, would be a number, and then the derivative of the number is just zero. I am still curious about the antiderivative... is there nothing that you can take the derivative of, to get earctan x?
 
Unfortunately, most functions do not have "nice" antiderivatives. The classic example is the error function:

\mbox{erf}(x) = \frac{2}{\sqrt{\pi}}\int_0^x e^{-t^2} dt

If we define elementary functions as exponentials, logs, algebraic functions (like polynomials and root extractions), and finite combinations (sums, products, etc) and compositions thereof (which, extending to complex numbers, allows you to include trigonometric functions and their inverses), then it can be proven there is no elementary function equivalent to the error function, nor to the antiderivative you've given here.
 
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hmm... interesting. I can't wait to learn all this.

one more question:

how do you write all the math symbols into these posts?
 
  • #10
very cool, thanks so much StatusX, you have been very helpful.:smile:
 

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