- #1

longball4153

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## Homework Statement

A horizontal stream of water from a fire-fighter's hose hits a vertical wall. The firefighter knows that 16.9 kg of water are emitted from the hose per second, and that the water has a speed of 45.5 m/s. At the instant when it hits the wall, the direction of the velocity vector of the water is 25.0 degrees BELOW the horizontal. Calculate the average force exerted by the water on the wall, assuming that the vertical component of the velocity vector of the water is unchanged but the horizontal component of the velocity vector is reversed when the water rebounds from the wall.

V

_{i}=45.5 m/s

m= 16.9 kg/s

ϴ= 25 Degrees BELOW the horizontal

## Homework Equations

P=mv

v

^{2}=v

_{o}

^{2}+2ax

## The Attempt at a Solution

P

_{o}=mv

_{o}

p

_{o}=16.9kg/s*45.5m/s

P

_{o}=768.95

Now I have the initial momentum. From here I am stuck and not sure where to go next. I know I need to somehow incorporate the angle given and calculate a final velocity. But then how would I take that and find an average force? Hopefully someone can explain/ show me the set up from here. Thanks!