The problem involves a diver falling from a height of 4.50 m into a swimming pool and the average force exerted on the diver during the deceleration phase after entering the water. The subject area includes concepts from mechanics, specifically impulse, momentum, and kinematics.
The discussion is active with participants exploring different interpretations of impulse and momentum. Some have provided calculations for the diver's final velocity and momentum, while others are questioning the assumptions regarding acceleration and the equations to use. There is no explicit consensus on the average force of the water on the diver.
Participants note the importance of distinguishing between the time taken to fall and the time taken to stop in the water. There is also mention of the gravitational force acting on the diver and its implications for the calculations.
This makes sense. It describes average force in terms of impulse and time.BuBbLeS01 said:Homework Equations
Favg = J/change in T
Huh? Where does this equation come from?J = 1/2 * Base * Height
I suppose J would equal the area of a Force vs. Time curve. But are you given any such curve in this problem? No.BuBbLeS01 said:I thought J was equal to the area under the curve (which is usually triangular shape).
That time is the time it takes him to stop once he hits the water. It's got nothing to do with the time he takes to fall the 4.5 m. (Also, realize that the speed is not constant as he falls.) You need a little kinematics to figure out the speed. (Or you can use energy methods, if that's easier for you.)BuBbLeS01 said:To find the speed I just did Distance/Time so I got 4.5m/1.58s = 2.85m/s
Good! Use that to find the momentum.BuBbLeS01 said:I get a final velocity of 9.396m/s