MHB What is the bearing and distance between cities A and C?

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The airplane flew from city A to city B on a bearing of 65 degrees, covering a distance of 60 km, and then from city B to city C on a bearing of S 25 degrees W for 86 km. To find the bearing of city C from city A, the Law of Cosines is applied to calculate the distance AC and angle BAC. The angle at point B is determined to be 40 degrees. By adding 65 degrees to the calculated angle BAC, the final bearing from A to C can be established. The discussion emphasizes the importance of using trigonometric laws for accurate navigation calculations.
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An airplane flew from city A on a bearing of 65 degrees to city B, a distance of 60km away. It then flew from B on a bearing of S 25 degree west to city C at a distance of 86km. Calculate (1) the bearing of C from A (ii) The distance between A and C
 
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Have you drawn a diagram yet?
 
Hello, Jerome!

An airplane flew from A to B on a bearing of 65o for 60km.
It then flew from B to C on a bearing of S 25o W for 86km.
Calculate (1) the bearing of C from A,
. . . . . . . (2) the distance between A and C.
Code:
                  B
      :           *
      :         */:
      :    60 * / :
      :     *  /  :
      :65[SUP]o[/SUP]* 40[SUP]o[/SUP]/25[SUP]o[/SUP]:
      : *    /    :
    A *     / 86  :
        *  /
          *
          C
You know: AB = 60,\;BC = 86,\;\angle B = 40^o

Use the Law of Cosines to find side AC.

Then use the Law of Cosines to find \angle BAC.
Add 65^o to find the bearing of AC.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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