What is the beat frequency of two strings with different tensions?

[nietzsche]

Homework Statement

Two strings with otherwise identical properties differ in tension by 0.25 N. If both strings are struck at the same time, what is the resulting beat frequency?

Homework Equations

frequency is proportional to the root of tension?

The Attempt at a Solution

I tried setting T₂ = T₁ - 0.25 N and substituting this into an equation with f₁/f₂ proportional to sqrt{T₁/T₂}.

But I can't seem to figure anything out from this.

Please help! Going a bit crazy.

 

[willem2]

I can't make anything of it either.

If I put f_1 = k \sqrt {T} and

f_2 = k \sqrt {T + 0.25}

I get

f_2 - f_1 = k \sqrt {T+0.25} - k \sqrt {T}

which I can't simplify further.

0.25 N is probably quite small compared to the tension in the string, so we can apply

\sqrt {T+0.25} \approx \sqrt {T} + 0.25 \frac {1} {2 \sqrt {T}}

this results in

f_2 - f_1 \approx \frac {0.125 k} {\sqrt{T}}

so the answer does depend on the tension, and the other properties of the string as well.

 

[nietzsche]

I can't make anything of it either.

If I put f_1 = k \sqrt {T} and

f_2 = k \sqrt {T + 0.25}

I get

f_2 - f_1 = k \sqrt {T+0.25} - k \sqrt {T}

which I can't simplify further.

0.25 N is probably quite small compared to the tension in the string, so we can apply

\sqrt {T+0.25} \approx \sqrt {T} + 0.25 \frac {1} {2 \sqrt {T}}

this results in

f_2 - f_1 \approx \frac {0.125 k} {\sqrt{T}}

so the answer does depend on the tension, and the other properties of the string as well.

thank you so much willem. i don't think my prof worded the question properly, so I'm going to ask him tomorrow. thanks again!