What is the caloric content of alcohol in a 6-oz glass of Sauvignon Blanc wine?

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The caloric content of alcohol in a 6-oz glass of Sauvignon Blanc wine, which contains 10.6% ethanol by mass, is calculated based on the heat of combustion of ethanol. A 6-oz glass (177 mL) yields approximately 18.762 grams of ethanol. Using the molecular weight of ethanol (46.06844 g/mol), this converts to about 0.407 moles of ethanol. The total energy released from combustion is -556,729 J, which translates to -2,329,355 calories when converted. The calculations emphasize the significant caloric contribution of ethanol in wine.
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Homework Statement


The heat of combustion of ethanol,C2H5OH(l}, is -1367kJ/mol. A batch of Sauvignon Blanc wine contains 10.6% ethanol by mass.

Assuming the density of the wine to be 1.0g/mL, what caloric content does the alcohol (ethanol) in a 6-oz glass of wine (177 mL) have?


Homework Equations


1 J = 4.184 Cal


The Attempt at a Solution


(177).106 = 18.762g of ethanol
Molecular weight of ethanol = 46.06844 g/mol
18.762/46.06844 = 0.40726 = mol
.40726 * -1367 * 1000 = -556729 J
-556729*4.184 = -2329355 Cal
 
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6021023 said:
-556729*4.184 = -2329355 Cal

Check your units.
 

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