What is the Cartesian form of 1/(2^j)?

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SUMMARY

The Cartesian form of the expression 1/(2^j) is derived using Euler's formula and properties of exponents. The conversion process involves rewriting 1/(2^j) as 2^-j, which can be expressed in exponential form as 2^(e^(-πj/2)). The real part, a, is calculated as cos(-π/2) resulting in 0, while the imaginary part, b, is sin(-π/2) yielding -1. Thus, the Cartesian form is 0 - 1j.

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Homework Statement



I solved this following problem but I am not sure whether I did this right: convert
(1/(2^j)) to cartesian form.

Homework Equations





The Attempt at a Solution



re^j\theta = a+jb

a=r cos \theta= cos -\pi/2
b= sin -\pi/2 = -1

1/(2^j) = 2^-j
=2^e^(-pi j /2)
=2^-j
 
Last edited:
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1/2^j=2^(-j) as you said. But to get to the e form use 2=e^ln(2).
 

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