What Is the Change in Momentum of a Golf Ball During Impact?

[BuBbLeS01]

Homework Statement

A golf ball with a mass of 43.80 g can be blasted from rest to a speed of 64.60 m/s during impact with a club head. Assume that the impact lasts only about 0.980 ms. Calculate the change in momentum of the ball.

Homework Equations

P = mv
Change in P = Pf - Pi
J = 1/2 base * height
Favg = J/Change in time

The Attempt at a Solution

Mg = .04380kg
Vi = 0m/s
Vf = 64.60m/s
Time = .00098s

A.) Change in P = (.04380kg * 64.60m/s) - (.04380kg - 0m/s) = 2.83kg*m/s RIGHT
B.) J = 1/2 * 0.00098s * 2.83kg*m/s = .001386
Favg = (0.001386N/s)/(0.00098s) = 1.415N WRONG...But I don't know why. I think it has to do with when I calculated J I am not sure if my height (Fmax) is supposed to be the 2.83kg*m/s.

 

[BuBbLeS01]

Okay maybe I don't need Fmax is J = Change in P??