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What is the coefficient of friction?

  1. Oct 10, 2011 #1
    1. The problem statement, all variables and given/known data

    A 500kg box is being pushed across a floor, with an applied force of 8400N, at a constant velocity, at an angle of 35 degrees below the horizontal. What is the coefficient friction between the floor and the box.

    2. Relevant equations

    I really do not know where to start.

    3. The attempt at a solution

    I know that Ff= (coefficient of kinetic friction)*mass*gravity
    and because it's at constant velocity Fp=Ff right?
    the answer is 0.71
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 10, 2011 #2
    You understand the most important part already.

    It's also important to realize though, that the applied force magnitude does not equal friction force, but it is a component of applied force that equals friction force.

    Also, we have a vertical component of the applied force that will effect your normal force.

    Can you find the i and j components of this 8400N force applied at your 35* angle?
     
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