What Is the Coefficient of Performance of a Carnot Heat Pump?

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SUMMARY

The coefficient of performance (COP) of a Carnot heat pump is defined as COP = Q_h / W, where Q_h is the heat delivered to the hot reservoir and W is the work input. The relationship between the heats can be expressed as Q_c / Q_h = - T_c / T_h, indicating that the heat extracted from the cold reservoir (Q_c) and the heat delivered to the hot reservoir (Q_h) are inversely related to their respective temperatures. The discussion highlights the importance of understanding sign conventions and the ideal behavior of a Carnot cycle, where the entropy variation of the system and surroundings must equal zero.

PREREQUISITES
  • Understanding of thermodynamic cycles, specifically the Carnot cycle.
  • Familiarity with the concepts of heat transfer and work in thermodynamics.
  • Knowledge of entropy and its role in reversible processes.
  • Ability to interpret equations and sign conventions in thermodynamic contexts.
NEXT STEPS
  • Study the derivation of the Carnot cycle equations and their implications for heat pumps.
  • Learn about the significance of sign conventions in thermodynamic equations.
  • Explore the concept of entropy in reversible and irreversible processes.
  • Investigate real-world applications and limitations of Carnot heat pumps.
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Students of thermodynamics, engineers working with HVAC systems, and anyone interested in the principles of heat transfer and energy efficiency in thermal systems.

~angel~
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This question is killing me because I just can't seem to get it.

A heat pump is used to heat a house in winter; the inside radiators are at T_h and the outside heat exchanger is at T_c. If it is a perfect (e.g., Carnot cycle) heat pump, what is K_pump, its coefficient of performance?

Give your answer in terms of T_h and T_c.

According to the hints, you're meant to work out the efficiency of the pump in terms of Q_c and Q_h. I thought it was 1 + (Q_c/Q_h)...

The textbook states that Q_c/Q_h = - T_c/T_h, but in the hints, it states Q_h/Q_c = T_h/T_c.

I'm totally confused.

Please help.
 
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I don't know how to solve the problem, but I wanted to point out that Q_h/Q_c = T_h/T_c and Q_c/Q_h = T_c/T_h are the same equation written differently. I don't know what the negative symbolizes, but if it was left out, then it must be somewhat arbitrary in meaning.

Hope this helps, good luck.
 
It might be confusing with redundant data. The expression should be Qh/(Qh-Qc) or Th/(Th-Tc)
 
~angel~ said:
The textbook states that Q_c/Q_h = - T_c/T_h, but in the hints, it states Q_h/Q_c = T_h/T_c.

I'm totally confused.

Please help.

I would say this equation represents such an ideal behavior of a Carnot heat pump. Entropy variation of the system must be 0 for being a cyclic machine, and entropy variation of universe (system+surroundings must be also 0 for being a reversible machine). So that the variation of entropy of the surroundings must counterbalance each other (in each focus).

On the other hand you should be careful with the sign convention. Maybe the book refers to different sign convention in each sentence. I always take the absolute value of the heats and put externally the convenient sign.

Also be careful because the COP of a heat pump is defined as COP=Q_h/W.
 

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