What is the comet's maximum speed at its farthest distance from the star?

AI Thread Summary
The discussion centers on calculating a comet's speed at its farthest distance from a star, given its speed at closest approach. The initial speed at a distance of 4 x 10^10 km is 50 km/s. A user attempts to apply gravitational and centripetal force equations but is advised to consider angular momentum conservation instead. By applying the conservation of angular momentum, the comet's speed at a distance of 10 x 10^10 km is determined to be 20 km/s. The conversation emphasizes the importance of using the correct principles for elliptical orbits.
johnsholto
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A comet orbits a star. At its closest approach (r=4*10^10 km) it has a speed of v=50 km/s. How fast is the comet at its maximum distance (R=10*10^10 km)?

Could someone verify my results?

F=GMm/r^2=mv^2/r

f=GMm/R^2=mV^2/R

F/f = R^2/r^2 = Rv^2/rV^2 -> R/r = v^2/V^2

R=2.5r -> 2.5r/r = v^2/V^2 -> V^2 = 2500/2.5 km^2/s^2 -> V = √1000 km/s
 
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The comet is moving in a very elliptical orbit rather than a circular orbit. You cannot take r and R as radii of circular motion. Try something else. (Hint: Use an appropriate conservation principle.)
 
What about angular momentum?

mvr=mVR

50*4*10^10=x*10*10^10

x=20
 
:smile:
 
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