What is the constant k in the form of solution y(t) = Aexp(kt)?

  • Thread starter Thread starter beanryu
  • Start date Start date
  • Tags Tags
    Constant Form
Click For Summary
SUMMARY

The discussion centers on determining the constant k in the exponential decay formula y(t) = Aexp(kt) for a radioactive substance that decays to 30% of its original amount in 440 days. The correct interpretation of the formula is clarified as y(t) = Ae^(kt), where A represents the initial amount. The value of k can be calculated using the decay formula, leading to the conclusion that k is negative, reflecting the decay process.

PREREQUISITES
  • Understanding of exponential functions and their properties
  • Basic knowledge of radioactive decay concepts
  • Familiarity with natural logarithms and their applications
  • Ability to manipulate equations involving exponents
NEXT STEPS
  • Calculate the decay constant k using the formula k = (ln(final amount/initial amount))/time
  • Explore the implications of negative k values in decay processes
  • Learn about other applications of exponential decay in different scientific fields
  • Investigate the relationship between half-life and the decay constant k
USEFUL FOR

Students in physics or chemistry, researchers studying radioactive materials, and anyone interested in mathematical modeling of decay processes.

beanryu
Messages
90
Reaction score
0
In 440 days, an unknown radioactive substance decays to 30 percent of its original amount.


(a) What is the constant k in the form of solution y(t) = Aexp(kt)?

k=?

First of all... I don't even know what Aexp(kt) mean

does it A^(kt) or what?!
 
Physics news on Phys.org
It means [tex]y(t)=Ae^{kt}[/tex]
 

Similar threads

Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
33K
Replies
1
Views
8K
Replies
7
Views
2K
Replies
4
Views
7K
Replies
8
Views
4K
Replies
1
Views
4K