What Is the Correct Calculation for Current in a Solenoid?

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SUMMARY

The correct calculation for the current in a solenoid with a length of 0.16 m and 130 turns of wire, producing a magnetic field strength of 2.0 mT, requires the use of the formula B = μNI/L. The permeability constant (μ) should be 4π x 10^-7 T·m/A in free space, not 2e-7. The current calculation must also convert the magnetic field from milliTesla to Tesla, resulting in a final current value of approximately 12.5 A.

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Homework Statement



A solenoid is 0.16 m long and consists of 130 turns of wire. At its center, the solenoid produces a magnetic field with a strength of 2.0 mT. Find the current in the coil.


Homework Equations


B=μNI/L B=strengh of magnet N=number of loops I= current and L=lengh μ is the constant 2e-7

The Attempt at a Solution


I plugged in 2mT=(2e-7)(130)(I)/.16m
I got 2mt=(.0001625)(I). I then did 2/.0001625 and got the current to equal 12,307.69 but it isn't right.What did I do wrong?
 
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hi tomsolo, and welcome to physicsforums :)
Ah, it looks almost correct, but there are two things that I'm not sure about. Why is μ equal to 2E-7 ? In free space it is roughly equal to 13E-7 Also, on the last line, you've got 12,307.69 but you still need to take into account that the magnetic field was in milliTesla.
 

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