What Is the Correct Derivative of 2v in the Context of Differentiation?

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SUMMARY

The correct derivative of the expression 2v in the context of differentiation is 2v', where v is a function of x. This conclusion arises from applying the chain rule, which indicates that when differentiating a function of another variable, the derivative must account for the dependency on that variable. In the given problem, the derivative is calculated as d/dx(2v) = 2dv/dx = 2v'. The final value of the derivative at x=1 is confirmed to be 14/9.

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Homework Statement



Find the value of the following derivative at x=1:

d/dx(2v/u)

where u(1)=3, u'(1)=-4, v(1)=-2, v'(1)=5


The Attempt at a Solution



Differentiating the equation:

[(u)(2v') - (u')(2v)]/(u^2)

plugging in the values i get 14/9 as the value.


now my question arises from the derivative of 2v. Would it be just 2? or 2v' as v represents a 'complex base' (therefore using the chain rule)??

the question seems simple enough to me as well but i just want to clarify this.

thanks.
 
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Hi g$up! Welcome to PF! :wink:
g$up said:
… now my question arises from the derivative of 2v. Would it be just 2? or 2v' as v represents a 'complex base' (therefore using the chain rule)??

The derivative (wrt x) of 2v is definitely 2v'. :smile:
 
To expand on what tiny-tim said, d/dv(2v) = 2, but with d/dx(2v) there's a tacit assumption that v is a function of x, so d/dx(2v) = 2dv/dx = 2v'. In this problem, both u and v are assumed to be differentiable functions of x.
 

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