What Is the Correct Formula for the Radius of Convergence?

Click For Summary
SUMMARY

The discussion centers on the formula for the radius of convergence of the series \(\sum \frac{n^2}{3^n z^n}\). The correct approach to determine the radius of convergence involves using the formula \(\frac{1}{R}=\lim_{n \to \infty}\sqrt[n]{|\sum \frac{n^2}{3^n z^n}|}\). Participants express skepticism about the validity of the proposed formula for \(1/R\) and seek clarification on the next steps in the analysis.

PREREQUISITES
  • Understanding of series convergence and divergence
  • Familiarity with limits and the concept of radius of convergence
  • Knowledge of power series and their representations
  • Basic proficiency in mathematical notation and operations
NEXT STEPS
  • Study the derivation of the radius of convergence for power series
  • Learn about the Ratio Test and Root Test for series convergence
  • Explore advanced topics in complex analysis related to series
  • Investigate the implications of convergence in the context of analytic functions
USEFUL FOR

Mathematicians, students studying calculus or complex analysis, and anyone interested in understanding series convergence and power series behavior.

lom
Messages
29
Reaction score
0
[tex]\sum \frac{n^2}{3^nz^n}\\[/tex]

[tex]\frac{1}{R}=\lim_{n->\infty}\sqrt[n]{|\sum \frac{n^2}{3^nz^n}|}\\[/tex]

what to do now?
 
Physics news on Phys.org
What's the question? Also, I don't believe that your formula for 1/R is correct.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K