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My Yes was premature, sorry. The answer to my ""Did you find the x-coordinate of the leftmost point of the "horizontal line where it join all the 15N and 10N" ? (It is not -4 )"" is not (-6, 0) but -6.
It is a coordinate. It is related to the x coordinates of the points where the 10 and 15 N forces act.
The position vector of this leftmost point is of course ##(-6, 6\sqrt 3)##. ##\ \ \ (-6,0)## would be on the x-axis to the left of O.
Can you now calculate the x-coordinate of the point where the leftmost 10 N force is acting ? (it is not 1, it is not -3 and the y-coordinate ##6\sqrt 3## you used is correct.)
And we still have to fix the y-coordinate of the point where the force P is acting. (it is not ##6\sqrt 3## ).
Almost there ..
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It is a coordinate. It is related to the x coordinates of the points where the 10 and 15 N forces act.
The position vector of this leftmost point is of course ##(-6, 6\sqrt 3)##. ##\ \ \ (-6,0)## would be on the x-axis to the left of O.
Can you now calculate the x-coordinate of the point where the leftmost 10 N force is acting ? (it is not 1, it is not -3 and the y-coordinate ##6\sqrt 3## you used is correct.)
And we still have to fix the y-coordinate of the point where the force P is acting. (it is not ##6\sqrt 3## ).
Almost there ..
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