What Is the Correct Minimum Velocity from Infinity?

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Homework Help Overview

The discussion revolves around a physics problem related to energy conservation and potential energy in the context of a charge moving from infinity towards a point of interest. Participants are examining the minimum velocity required for the charge to reach the finish line, considering the effects of potential energy changes along the path.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of energy conservation principles, questioning the original poster's calculations and the assumptions made regarding potential energy and kinetic energy relationships. There is a focus on understanding the implications of the potential energy "hill" that affects the charge's motion.

Discussion Status

The discussion has progressed with participants providing insights into the nature of the problem, particularly regarding the non-monotonic force acting on the charge. Some guidance has been offered about the implications of the potential energy landscape, but there is no explicit consensus on the correct approach or final answer.

Contextual Notes

Participants note that the original poster's calculations may not account for the additional energy required to overcome the potential energy hill, which complicates the determination of the correct minimum velocity. There is an acknowledgment of the complexity of the problem and the need for careful consideration of energy changes along the trajectory.

cupid.callin
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Homework Statement


<In Pic 1>


Homework Equations



(1/2)mv2 = ΔU



The Attempt at a Solution



I thought that if i apply the equations i'll have my answer but i got 2.5m/s while answer is 3m/s

Please refer the solution given by some book --- Pic2, Pic3
<sorry for bad image, my scanner nt working properly o.O >

Please tell me what is wrong i my method?
 

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What method? You haven't shown what you've done, only what the book solution is.
 
I mentioned it that i used energy conservation:

decrease in kinetic energy from infinity to 0 results in inc. in potential energy

My work's in pic
 

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Ah. Well, the problem is that the force upon the charge as it moves inwards from infinity is not monotonic. It changes sign (direction) along its path. If you plot the potential along the trajectory, you'll see that there's a significant "hill" in the way that the charge has to climb and then ride down towards the origin.

The energy the particle needs to get over the hill is the energy it needs to have at infinity. Once it has cleared the top of the hill, it can just 'roll' down to the finish line, gaining KE accordingly. If it just barely has enough initial energy to reach the top of the hill (making its velocity approach zero), then the KE it will have at the finish line will be equal to the PE at the top of the hill minus the PE at the finish line.
 
But then my answer should have been more than the correct answer, isn't it?

But i got 2.8 but answer is 3
 
No, your answer should be less than the real answer because the hill is higher than the finish line. You calculated the energy required as the difference between the potential at infinity and at the finish line (origin). The hill in between means that more initial energy is required to make it to the finish line.
 
OH!

Now i get it ... that was one tricky question

thanks for your help gneill
 

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