What is the correct Taylor expansion for sin x around -pi/4 to the fourth term?

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SUMMARY

The correct Taylor expansion for sin x around -π/4 to the fourth term is given by the formula: sin(-π/4) + cos(-π/4)(x + π/4) - 0.5sin(-π/4)(x + π/4)² - (1/6)cos(-π/4)(x + π/4)³. Evaluating sin(-π/4) and cos(-π/4) yields -√2/2 and √2/2, respectively. The mistake in the initial calculation likely stems from incorrect application of the Taylor series formula or miscalculation of the coefficients.

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pantheid
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I am asked to solve the taylor expansion of sin x around the point -pi/4 to the fourth term.

I got sin(-pi/4)+cos(-pi/4)(x+pi/4)-.5sin(-pi/4)(x+pi/4)^2-1/6(cos(-pi/4)(x+pi/4)^3 but I am getting it wrong and can't see my mistake.
 
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Try evaluating for sin(-π/4), cos (-π/4),etc. It appears to be right.
 

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