What Is the Correct Way to Calculate Net Torque?

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SUMMARY

The correct method to calculate net torque about point O involves using the formula τ = F * d * sin(θ), where τ is torque, F is the force applied, d is the distance from the pivot point, and θ is the angle between the force and the lever arm. In this discussion, the user calculated the torque from a 12N force at a 30-degree angle and an 8N vertical force. The final answer for net torque was determined to be -12 Nm, indicating a clockwise rotation. The confusion arose from neglecting the y-component of the angled force and miscalculating the angles involved.

PREREQUISITES
  • Understanding of torque and its calculation
  • Familiarity with trigonometric functions, particularly sine
  • Knowledge of forces and their components
  • Basic principles of rotational motion
NEXT STEPS
  • Study the concept of torque in physics, focusing on the formula τ = F * d * sin(θ)
  • Learn about resolving forces into components, especially in angled applications
  • Explore examples of torque calculations in different scenarios
  • Investigate the effects of clockwise and counterclockwise torques on rotational equilibrium
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Students studying physics, particularly those focusing on mechanics, engineers involved in design and analysis of rotating systems, and anyone interested in understanding the principles of torque and rotational dynamics.

trajan22
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Calculate the net torque about point O for the two forces applied as in the figure View Figure . The rod and both forces are in the plane of the page. Take positive torques to be counterclockwise.

A image is here to show the problem

What i did
12Nsin(30)*(2m)-(8N*3m)
or if you like this better
F2sin(theta)*d-(F1*d)
however this isn't working should i not be neglecting the y component of F2 or do i have the angle wrong...i am confused any help is appreciated.

it appears my image is taking forever to get approval so i will try and explain the problem.
there is a rod where the axis of rotation is on the left end of it
2 meters from this axis is a force going up and to the left, at a 30 degree angle. with a magnitude of 12N (F2)
Another force is a total of 5 meters from the point of rotation and is vertical with a magnitude of 8N (F1)
nevermind i turned out to be right...i just made a dumb error.
 

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i'm confused as to how to come up with an answer, trajan22. did you happen to get -12 ..clockwise for the answer??
 

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