What is the Cosine Rule for Triangles with Operands Greater Than 1?

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Homework Help Overview

The discussion revolves around the application of the Cosine Rule in the context of a Mechanics problem involving the resultant of two forces. The original poster encounters difficulty in determining the direction of the resultant force due to an operand exceeding 1 when attempting to rearrange the Cosine Rule to find an angle.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the conditions under which the Cosine Rule is applicable, question the original poster's calculations, and discuss the relationship between angles and sides in triangles. There is also mention of the Sine Rule as an alternative approach.

Discussion Status

The discussion includes various interpretations of the Cosine Rule and its application. Some participants provide guidance on the correct usage of the rule, while others express confusion regarding the original poster's calculations and assumptions. There is no explicit consensus on the resolution of the problem.

Contextual Notes

Participants note that the Cosine Rule is typically used when the angle is opposite the longest side of the triangle, and there is a suggestion that the original poster may have misapplied the formula. The discussion also highlights the existence of multiple forms of the Cosine Rule for different angles and sides.

W3bbo
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Homework Statement



As part of a Mechanics problem, I need to find the resultant of two forces. I was able to find F[Resultant]'s magnitude easily enough, but it's direction stumps me.

...because when I rearrange the Cosine rule to find angle A, the operand of Arccos is greater than 1.

Homework Equations



See attachment

The Attempt at a Solution



No idea :confused:
 

Attachments

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Then you have erred in your calculations.
 
arildno said:
Then you have erred in your calculations.

Turns out my calculations were fine, I just forgot the Cosine rule was only of use when A is opposite the longest side in any given triangle.

I just needed to use regular Sine Rule to find the missing angle.

Problem solved.
 
W3bbo said:
Turns out my calculations were fine, I just forgot the Cosine rule was only of use when A is opposite the longest side in any given triangle.

Incorrect, wherever have you gotten that strange idea from?
 
yes largest angle is always opposite the longest side (common sense) BUT that doesn't mean you can only use cosine rule on that angle.
just reading the maths it is very hard for me to deduce what does your force diag looks like and what are you trying to solve...but just looking at the cosine rule it seems wrong (normal symbol usage assumed) should be
[tex]a^2=b^2+c^2-2bc \cos A[/tex] where A is angle opposite side a.
 
There are actually three "cosine rules" for any triangle.
[tex]a^2= b^2+ c^2- 2bc cos(A)[/tex]
[tex]b^2= a^2+ c^2- 2ac cos(B)[/tex]
[tex]c^2= a^2+ b^2- 2ab cos(C)[/tex]
Whate a is the length of the side opposite angle A, b is the length of the side opposite angle B, and c is the length of the side opposite angle C.

Your original formula was [itex]a^2= b^2+ c^2- 2ab cos(C)[/itex], none of the above.
 

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