The diagram below depicts an RC-circuit where C = 1.70 μF, R1 = 18.0 Ω, R2 = 10.0 Ω, and V0 = 2.0 V.
a.) What is the current through R1 immediately after the switch S is closed?
b.) What is the current through R2 after the switch S has been closed for a very long time? Assume that the battery does not go dead.
The Attempt at a Solution
I got part A. I divided 2V by 18Ω to get 0.111A which is correct. I know when the switch is initially closed current flows through the capacitor and when it is charge current no longer flows through. I figured part B you would just find the current through 2/(18+10)=0.0714 which turned out incorrect so I'm not sure what to try next. Also I don't think the capacitance is relevant, so I hope I'm not wrong there. Any help would be great
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