What is the decibel level of a sound at 4% intensity of a 95dB sound?

  • Thread starter Thread starter slaw155
  • Start date Start date
  • Tags Tags
    Intensity
Click For Summary
To determine the decibel level of a sound at 4% intensity of a 95dB sound, the formula dB = 10log(I/I0) is used, where I0 is the reference intensity. First, calculate 4% of the intensity corresponding to 95dB, which is I = 0.04 * I95dB. Applying the logarithmic properties, the decibel level can be derived as dB = 10log(0.04 * I95dB/I0). The calculation results in a lower decibel level, reflecting the reduced intensity. This method effectively incorporates the percentage into the decibel calculation.
slaw155
Messages
41
Reaction score
0
What is the decibel level of a sound whose intensity is 4% that of a 95dB sound?

I know dB = 10log(I/Io) but don't know how to incorporate this for this question.
 
Physics news on Phys.org
Look at incorporating the percent to the I in the formula and then use log rules to pull out the percent factor.
 
Thanks solved it
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
18
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
850