What is the Definition of Compactification for a Topological Space?

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Hi guys, I am confused about the definition of compactification of a topological space.

Suppose (X,τx) is a topological space. Define Y=X\cup{p} and a new topology τY such that U\subseteqY is open if
(1) p \notin U and U\in \tauX or
(2) p \in U and X-U is a compact closed subset of X.

To prove that (Y,τY) is compact, it seems to require X-U in (2) to be compact under τY and not τX. That is if p\in U, then any open covering {Vi}\subseteqτY of Uc=X-U, has a finite subcover. But we don't even know what our open sets {Vi} are in the first place.

Any help would be appreciated.
 
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The induced topology of X as a subspace of Y is the same as the original topology of X (this is not obvious, but not hard to prove, just some definition chasing), so if we have
A\subset X \subset Y

A is compact in the topology of Y if and only if it is compact in the topology of X
 
Ah, I see. Thanks very much.
 
A sphere as topological manifold can be defined by gluing together the boundary of two disk. Basically one starts assigning each disk the subspace topology from ##\mathbb R^2## and then taking the quotient topology obtained by gluing their boundaries. Starting from the above definition of 2-sphere as topological manifold, shows that it is homeomorphic to the "embedded" sphere understood as subset of ##\mathbb R^3## in the subspace topology.

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