What is the Derivative of f(x) = Integral from x to x^2 t^2 dt?

  • Thread starter Thread starter intelli
  • Start date Start date
  • Tags Tags
    Integral
Click For Summary

Homework Help Overview

The problem involves finding the derivative of a function defined as an integral, specifically f(x) = ∫ from x to x² of t² dt. Participants are tasked with determining f'(x) and evaluating it at x = 5.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss breaking down the integral and applying the Fundamental Theorem of Calculus (FTC) to find the derivative. There are attempts to express the derivative in different forms and questions about the correctness of their answers based on feedback from an online program.

Discussion Status

There is ongoing exploration of the correct approach to differentiate the integral without fully integrating it. Some participants express confusion over the feedback received from the program regarding their answers, while others suggest experimenting with different formats for the answers.

Contextual Notes

Participants mention that the feedback from the program indicates their answers are incorrect, leading to discussions about potential issues with input formatting or misunderstanding of the question's requirements.

intelli
Messages
19
Reaction score
0

Homework Statement



f(x) = integral from x to x^2

t^2 dt

find f ' (x) = ?
find f '(5)= ?

Homework Equations





The Attempt at a Solution



Break the integral in 2: \int_x^{x^2} t^2 dt = \int_x^{0} t^2 dt +\int_0^{x^2} t^2 dt = -\int_0^{x} t^2 dt + \int_0^{x^2} t^2 dt
Then take the derivative of both integrals using the FTC.
 
Physics news on Phys.org


You don't even need to integrate the expression if you already learned the fundamental theorem of calculus (just be careful with your variables!). Where are you having difficulty?
 


This was my ans and it says that it is wrong
f ' (x) = -x^3/3+x^6/3

f ' ( 5 ) = 5166.666667

i also put

f ' ( x) = -x^2 + x ^ 4 and that was also wrong
 


What are you using that says it is wrong? Is it a book? A program? Because sometimes a program requires input a special way.
 


djeitnstine said:
What are you using that says it is wrong? Is it a book? A program? Because sometimes a program requires input a special way.

it is a program online i put the top ans on the program right but it says that both are incorrect ans for the f'(x) and f'(5)
 


Figures, try putting your answer in different forms.

Such as (x^6)/3-(x^3)/3

and 5166.7

etc... I don't know exactly what they want, but you should experiment to see what format they accept.
 


intelli said:
This was my ans and it says that it is wrong
f ' (x) = -x^3/3+x^6/3

This is not true, f(x) is defined as [itex]f(x)=\int_x^{x^2} t^2 dt=-x^3/3+x^6/3[/itex]. Now the ' means that you have to differentiate to x.
 


Cyosis said:
This is not true, f(x) is defined as [itex]f(x)=\int_x^{x^2} t^2 dt=-x^3/3+x^6/3[/itex]. Now the ' means that you have to differentiate to x.

good looking I didn't even see the '
 


intelli said:
This was my ans and it says that it is wrong
f ' (x) = -x^3/3+x^6/3

That is indeed incorrect. You are giving f(x), while the question asks for f'(x). Once again, note that there is no need to integrate the expression. Use the fundamental theorem of calculus.
 
  • #10


slider142 said:
That is indeed incorrect. You are giving f(x), while the question asks for f'(x). Once again, note that there is no need to integrate the expression. Use the fundamental theorem of calculus.

thanks a lot guys i figured it out
 

Similar threads

Replies
2
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
11K
Replies
12
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
3K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K