avito009
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In the book that I am reading the derivative of y = bpx is bpxxlogep. How?
Well the b and p in this case I'm assuming is a constant. Is it?avito009 said:In the book that I am reading the derivative of y = bpx is bpxxlogep. How?
Assuming that b and p are constants,avito009 said:In the book that I am reading the derivative of y = bpx is bpxxlogep. How?
Er... ln(y) = ln(b) + x⋅ln(p)...Mark44 said:Assuming that b and p are constants,
1. Take the natural log of both sides.
ln(y) = ln(bpx) = ln(b) + pln(x)
I edited my post to fix my error...Svein said:Er... ln(y) = ln(b) + x⋅ln(p)...