What is the diameter of the hole for a flow rate of 4.17x10-5 m3/s?

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SUMMARY

The diameter of a hole in a tank, which allows a flow rate of 4.17x10-5 m3/s, can be calculated using Bernoulli's theorem. The hole is located 15 m below the water level, where the total pressure is given by the equation Pa + ρgh. By determining the velocity of the liquid exiting the hole and applying the formula R = A*V, where R is the flow rate, the area of the hole can be derived, leading to the calculation of its diameter.

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Homework Statement


A large tank is filled with water and open to the atmosphere has a small hole in its side at a point 15 m below the water level. If the rate of flow from the hole is 4.17x10-5 m 3/s .
What is the diameter off the hole (in mm)

Homework Equations


R=A*V, where R is the rate flow
 
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In side the tank at the depth h the total pressure = Pa + ρgh. Velocity of the the liquid is zero.
Out side the hole the pressure = Pa.
Using Bernoulli theorem find the velocity of liquid flowing out of the hole, From that find the area of the hole.
 

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