What is the differential equation for a time-constant calorimetry experiment?

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SUMMARY

The differential equation for a time-constant calorimetry experiment involving a copper sample is defined as C*d/dt(T) = V^2/Rh - k(T-Ts), where C represents the heat capacity, V is the voltage across the heater coil, Rh is the electrical resistance of the heater coil, k is the thermal conductance, and Ts is the temperature of the reservoir. The equation models the heat added to the system and the heat lost to the reservoir, assuming perfect thermal equilibrium among the sample, heater, and thermometer. This linear coupled system can be solved using standard techniques for differential equations.

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Hello PF. I am an undergraduate in physics doing some work in a research lab at school and I need some help with a time-constant calorimetry experiment I am working on.

I am attempting to compute the temperature as a function of time of a small sample of copper that I am heating. I am modeling the setup as if the sample, the heater, and the thermometer are all in perfect thermal equilibrium (infinite thermal conductance between all three) and some thermal resistance R to a constant temperature reservoir to which heat is lost.

I have come up with the following differential equation to describe this situation:

d/dt(Q) = C*d/dt(T) + R(T-Ts) where Q is the heat added, T is the temp of the sample/thermometer, R is the thermal resistance between the sample and the reservoir and Ts is the temp of the reservoir.

I am hoping that someone can help me determine if the above is correct and if so give me some pointers on how to solve this diff-eq. I believe this is a linear coupled system and I don't know where to start. I really appreciate the help!
 
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I figured it out and so I thought I would post the answer for anyone with a similar problem although I realize this is probably very trivial for most...

C*d/dt(T) = d/dt(Q) where d/dt(Q) is the difference of the power being applied from the heater an the power being lost to the reservoir.

C*d/dt(T) = V^2/Rh - k(T-Ts) where V is the voltage across the heater coil, Rh is the electrical resistance of the heater coil, k is the thermal conductance of the link from the sample to the reservoir and C is the heat capacity of the apparatus including sample, heater and thermocouple etc.
 

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