What is the dimension of the impulse response of an electric circuit?

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SUMMARY

The impulse response h(t) of an electric circuit is the derivative of the step response s(t). If the dimension of s(t) is X, then the dimension of h(t) is X per second, indicating a difference in dimensions. In cases where the output dimension matches the input dimension, such as voltage-in and voltage-out, the dimension of h(t) must be the reciprocal of time to ensure proper functioning of the convolution integral, y(t) = ∫ h(t-u) x(u) du.

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asmani
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Hi all

The impulse response h(t) of an electric circuit (maybe in some special cases) is the derivative of the step response s(t) of the same circuit. right?
So does it mean they have different dimension, namely if the dimension of s(t) is X, then the dimension of h(t)=ds/dt is x over second?

Thanks in advance.
 
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asmani said:
The impulse response h(t) of an electric circuit (maybe in some special cases) is the derivative of the step response s(t) of the same circuit. right?
So does it mean they have different dimension, namely if the dimension of s(t) is X, then the dimension of h(t)=ds/dt is x over second?

okay, let's say that your impulse response is for a device in which the dimension of the output is the same as the dimension of the input. like voltage-in, voltage-out (but it could be current in/out or something else).

then, for the convolution integral to work

y(t) = \int_{-\infty}^{+\infty} h(t-u) x(u) du = \int_{-\infty}^{+\infty} h(u) x(t-u) du

the dimension for h(t) must cancel the dimension of the du which we normally attach to "time". so the dimension of h(t) is the reciprocal of time.
 

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