What is the direction of propagation for a wave

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Homework Help Overview

The discussion revolves around understanding the direction of propagation for a wave described by the function f = cos(x + 2y - vt). Participants are exploring how the wave behaves in the x-y plane and what defines its direction of movement.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are examining how the wave's properties change with respect to time and position in the x-y plane. Questions are raised about the significance of the direction vector (2,1) and how it relates to the wave's behavior. There is also discussion about the implications of the wave's dependence on both x and y coordinates.

Discussion Status

The discussion is active, with participants sharing insights and questioning the nature of wave propagation in a multi-dimensional context. Some guidance has been offered regarding the relationship between the wave's mathematical representation and its physical interpretation, but no consensus has been reached.

Contextual Notes

Participants are considering the implications of the wave's dependence on both spatial dimensions and time, as well as the potential complexity introduced by these factors. There is an acknowledgment of the need for clarity regarding the definition of direction in the context of the wave's behavior.

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for a wave of this type, for example:

f = cos(x+2y -vt)

What is then the definition of the direction of progation in the x-y plane? Because either way you go in the x-y plane the wave changes.
 
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If you plot f = cos(x) you get a nice sine wave that's not moving because it's independent of time. If you plot f = cox(x - vt) it appears to move in the x direction with time.

Think of it like this...

Pick a point on the x axis. Let's choose x=5 and note the value of f at that point at t=0. Then we want to know what the value of f will be at the same place (x=5) in the future. Let's define the future as t0+1. Let's also assume v=1 to make the sums simpler..

The new value of f at t0+1 will be cos(5-1) which equals Cos(4). In other words the value of f at x=4, t=0 moves to position x=5, t=1 Therefore the wave move towards increasing x (eg the right normally).
 
well I am with you on this. But only now we have that the wave is also dependent on x and y. And surely anywhere you move in the x-y plane will alter the look of the wave. What is it that makes the direction (2,1) so special? (note that the function was cos(2x+y-vt)
 
Something like Cos(x+y) is a surface with waves in straight lines. The line x+y=0 corresponds to a crest for example. Same with Cos(2x+y). The line 2x+y=0 corresponds to a crest.

The vt part simply changes the phase so the waves appear to move perpendicularly to the crest but in reality none of the points on the wave move sideways at all. Each point is only ever going up and down in the vertical f axis.

You can actually see what the surface looks like using Excel. Create a table and fill it with data using =COS(2*B$1-$A2). Create a chart using the surface option..

Ignore all the numbers on this plot as I couldn't be bothered to tidy it up..
 

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