What is the displacement and velocity of a falling object after 1.0 s?

  • Thread starter Thread starter Lana Elcic
  • Start date Start date
  • Tags Tags
    Fall Free fall
AI Thread Summary
A rock is thrown downward from the Verrazano Narrows Bridge with an initial velocity of 10.5 m/s, and the task is to calculate its displacement and velocity after 1.0 second. The displacement is calculated using the formula, resulting in -15.4 m. The gravitational acceleration of 9.8 m/s² is acknowledged as a constant factor in the calculations. The discussion emphasizes the importance of understanding acceleration as the rate of change of velocity to find the final velocity at 1.0 seconds. The calculations for both displacement and velocity are essential for solving the problem accurately.
Lana Elcic
Messages
40
Reaction score
0

Homework Statement


A rock is thrown straight down with an initial velocity of 10.5 m/s from the Verrazano Narrows Bridge in New York City. The roadway of this bridge is 70 m above water. Take upwards to be the positive direction.

Calculate the displacement and velocity at a time of 1.0 s.

The attempt at a solution
-5.6
 
Physics news on Phys.org
Lana Elcic said:

Homework Statement


A rock is thrown straight down with an initial velocity of 10.5 m/s from the Verrazano Narrows Bridge in New York City. The roadway of this bridge is 70 m above water. Take upwards to be the positive direction.

Calculate the displacement and velocity at a time of 1.0 s.

The attempt at a solution
-5.6

So what is your question?

Can you give some more details on how you ended up with that answer?
 
I've figured out the displacement by (10.5)(1)+(1/2)(9.8)(1.0)^2=-15.4
I don't know how to find velocity though.

C. Lee said:
So what is your question?

Can you give some more details on how you ended up with that answer?
 
Lana Elcic said:
I've figured out the displacement by (10.5)(1)+(1/2)(9.8)(1.0)^2=-15.4
I don't know how to find velocity though.

Alright.

So, you have used the gravitational acceleration 9.8m/s^2 to calculate the displacement.

What is the definition of acceleration?
 
rate of change of velocity

C. Lee said:
Alright.

So, you have used the gravitational acceleration 9.8m/s^2 to calculate the displacement.

What is the definition of acceleration?
 
Lana Elcic said:
rate of change of velocity
Right. So the acceleration is constant, and you are given with initial velocity. You can now calculate the velocity at t = 1.0 s.
 
Awesome! Thanks a lot

C. Lee said:
Right. So the acceleration is constant, and you are given with initial velocity. You can now calculate the velocity at t = 1.0 s.
 
Back
Top