What is the electric field amplitude 2m from the source

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Homework Help Overview

The original poster presents a problem involving a 60 W monochromatic point source radiating in a vacuum and seeks to determine the electric field amplitude at a distance of 2m from the source. The context involves concepts from electromagnetism and wave physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between intensity and amplitude, with one participant providing a formula involving the electric field. The original poster has calculated the intensity but is uncertain about the next steps. Another participant raises a separate but related question regarding the relationship between intensity and voltage in a circuit, seeking clarification on the logarithmic relationship.

Discussion Status

The discussion includes attempts to clarify the relationship between intensity and electric field amplitude, with some guidance offered on relevant equations. However, there is no explicit consensus on the next steps for the original poster's problem. The separate question about the LDR circuit has prompted a reminder about thread etiquette, indicating a need for clearer organization in the discussion.

Contextual Notes

The original poster's problem involves assumptions about the uniformity of radiation and the properties of the medium (vacuum). The second question introduces a different context that may not directly relate to the first, highlighting potential confusion in the discussion.

kingyof2thejring
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Homework Statement


A 60 W monochromatic point source is radiating equally in all diresctions in a vacum. What is the electric field amplitude 2m from the source.


Homework Equations


Intensity=Power/(4*Pi*r^2), Intensity proportional to square Amplitude


The Attempt at a Solution


I=1.19 Wm-2 what happens next?
 
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Use I=(1/2)\epsilonzero c E^2.
 
Desperate semi related question. If you have a graph of log intensity against log of (voltage across an LDR in a potential divider circuit)
how do you explain the relationship if your resultant is a straight line of -1.7 obviously in the form of y=mx+c
Log(y)= nlog(x) + logm where y is intensity and x is voltage n being -1.7 and logm being y intercept.
im trying to explain the relationship between the two quantities and ... I am stuck if anyone can help me i would very much appreciate it...
 
hopeless blonde said:
Desperate semi related question. If you have a graph of log intensity against log of (voltage across an LDR in a potential divider circuit)
how do you explain the relationship if your resultant is a straight line of -1.7 obviously in the form of y=mx+c
Log(y)= nlog(x) + logm where y is intensity and x is voltage n being -1.7 and logm being y intercept.
im trying to explain the relationship between the two quantities and ... I am stuck if anyone can help me i would very much appreciate it...

Welcome to PF, hopeless blonde. In future, however, please don't hijack another person's thread with your own question-- instead, start a new thread in the relevant homework section.

With regard to your question, you have an equation of the form logy=nlogx+logm. Now, nlogx can be expressed as log(xn). Do you know a rule for loga+logb?
 

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