What Is the Electric Field Magnitude at r for Concentric Spheres?

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SUMMARY

The discussion focuses on calculating the electric field magnitude at a distance r from the center of three concentric spheres with radii a, b, and c, where a > b > c. The outer surface charge densities are σ, -σ, and σ, respectively. The derived formula for the electric field at a point where a > r > b is confirmed to be 4πb²/r², aligning with the standard electrostatic principles. The initial calculation presented by a participant was corrected to reflect the influence of the charge distributions accurately.

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  • Understanding of electrostatics and electric fields
  • Familiarity with Gauss's Law
  • Knowledge of concentric spherical charge distributions
  • Basic calculus for manipulating equations
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  • Study Gauss's Law applications in electrostatics
  • Explore electric field calculations for different charge configurations
  • Investigate the effects of varying charge densities on electric fields
  • Learn about the implications of spherical symmetry in electric fields
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Students of physics, electrical engineers, and anyone studying electrostatics and electric field theory will benefit from this discussion.

divr
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There are three concentric thin spheres of radii a,b, c (a>b>c). The outer surface charge densities of their surfaces are σ, -σ and σ respectively. Find the magnitude of electric field at r (distance from centre) such that a>r>b ??

My answer was,

Er = [ K σ . 4 (pi) c2 / r2 - K σ . 4 (pi) b2 / r2 ]

But the answer is given as,

4(pi) b2 / r2
 
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If 1/K=epsilon, I think your answer is correct.
 

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