What is the Enthalpy of Formation for Copper (II) Chloride?

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Discussion Overview

The discussion centers around the enthalpy of formation for copper (II) chloride (CuCl2), specifically how to calculate it based on experimental data regarding the heat released during the reaction of copper with chlorine. The scope includes theoretical reasoning, calculations, and potential misunderstandings related to Hess's Law.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a calculation based on the heat released (2.06 kJ) when 0.365 g of copper reacts, leading to multiple proposed answers for the enthalpy of formation.
  • Another participant questions the logic behind the chosen answer and suggests writing out the chemical reaction and finding the molar ratios involved.
  • A participant expresses frustration at not arriving at the correct answer and suggests that the correct enthalpy of formation should be -358 kJ/mol, indicating a possible error in the provided options.
  • One participant explains that the enthalpy of formation for CuCl2 can be derived from the measured heat change and the moles of CuCl2 produced, emphasizing the need to divide the total heat change by the number of moles to find the per mole value.
  • Several participants inquire about the origin of the -2.06 kJ value, with one clarifying that it is derived from the experimental observation of heat released, noting the importance of the negative sign for exothermic reactions.

Areas of Agreement / Disagreement

Participants express differing views on the correct enthalpy of formation value, with some supporting the calculation leading to -358 kJ/mol while others work through the provided options without reaching consensus on the correct answer.

Contextual Notes

Participants highlight the importance of understanding the relationship between heat released and moles of product formed, as well as the significance of elemental states in determining enthalpy of formation. There are unresolved calculations and assumptions regarding the enthalpy values presented.

Who May Find This Useful

This discussion may be useful for students studying thermodynamics, particularly those interested in enthalpy calculations and the application of Hess's Law in chemical reactions.

ashooazmi
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Hey guys this is my 1st post here...Need help with a question that's been troubling me for a long time...

A student determined experimentally that 2.06 kJ of heat energy were released when 0.365 g of copper reacted with excess chloride. From these data, the enthalapy of formation of copper (II) chloride would be...
a. -206 kJ/mol
b. -1.09 kJ/mol
c. +2.71 kJ/mol
d. +165 kJ/mol


please help because its frustrating me - when i picked b. my teacher said its WRONG ! I don't get it at all. I think area it is focussing on is Hess's Law! Please help me! :confused:

Thanks in advance,
Me
 
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How did you arrive at answer b? What was your logic, if any?

-Write out the chemical reaction.
-Find the molar ratio of Cu reacted to CuCl2 produced.
-Convert the given number of grams of Cu into moles of Cu.
-Use the mole ratio calculated earlier to find the number of moles of CuCl2 produced.
-Find a relationship between the heat energy measured to be given off and the number of moles of CuCl2 produced.

Remember that the enthalpy of formation of a substance in its pure, elemental, state is zero.
Copper metal [Cu (s)] and Chlorine gas [Cl2 (g)] are both in their elemental states in this reaction, therefore the only thing that has a non-zero enthalpy of formation would be the CuCl2.
 
I still can't get the right answer i am fumbeling around -358?
 
-Write out the chemical reaction.
Cu(s) + Cl2 (g) ----> CuCl2

-Find the molar ratio of Cu reacted to CuCl2 produced.
1:1

-Convert the given number of grams of Cu into moles of Cu.
0.365/63.55 = 0.0057435 mol Cu

-Use the mole ratio calculated earlier to find the number of moles of CuCl2 produced.
0.0057435 mol Cu

-Find a relationship between the heat energy measured to be given off and the number of moles of CuCl2 produced.
??
 
Sorry Guys I worked on it over and over and over again but couldn't get the RIGHT ANSWER - b/c THE RIGHT ANSWER ISN'T THERE! It should be - 358 kJ/mol . I showed my work to me intructor and she did the problem with me - realizing that she had messed up!
 
For others' benifit,
ashooazmi said:
-Find a relationship between the heat energy measured to be given off and the number of moles of CuCl2 produced.
??
The change in enthalpy in the reaction is the sum of the enthalpies of formation of the products minus the sum of the enthalpies of formation of the reactions.
Since both Cu(s) and Cl2 (g) have a zero enthalpy of formation, we know the only thing which is left to cause the final change in enthalpy is the CuCl2.
Enthalpy of formation of CuCl2 - 0 = enthalpy of formation of CuCl2.
We measured the change in enthalpy of the reaction to be -2.06 kJ and you have previously calculated that 0.0057435 mol [CuCl2] produced in the reaction. We are looking for a value of enthalpy per mol not per 0.0057435 mol, so dividing the measured delta H by the number of moles of CuCl2 gives is the change in enthalpy per mole of CuCl2 which we also know to be the enthalpy of formation of CuCl2.

b/c THE RIGHT ANSWER ISN'T THERE
So you had it right earlier but you just didn’t trust your answer since it wasn’t one of the choices.
If something like this happens again on a homework question you might try checking your calculated answer with a reference table to see how close you got. If your answer is sufficiently close to the reference table's value then this will give you more confidence when questioning the teacher. (of course this solution isn’t practical when it comes to taking tests obviously)
 
How did you get the -2.06 kJ? Is there a formula to find that answer? I keep seeing these numbers, but I don't see how you get that number.
 
Enthalpy help too...

How did you get the -2.06 kJ? Is there a formula to find that answer? I keep seeing these numbers, but I don't see how toget it.
 
I got the value of -2.06 kJ from the question.

The question stated,
A student determined experimentally that 2.06 kJ of heat energy were released when 0.365 g of copper [...]
The key phrase being,
"2.06 kJ of heat energy were released".
Since the heat was released the sign on the delta H value must be negative to make it an exothermic reaction.

There is a formula to find the change in enthalpy of the reaction,
(delta H) = (sum of enthalpies of formation of products) - (sum of enthalpies of formation of reactants)

In this case, since all the reactants in the chemical reaction were in their elemental states, their enthalpies of formation were zero, leaving the only non-zero enthaly of formation that of the CuCl2...a product of the reaction, so,
delta H = enthalpy of formation of CuCl2
 
  • #10
thank you for your reply it clarified a lot
 

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