What is the equation for calculating tension in an elevator rope?

[B-80]

An elevator and its load have a combined mass of 1500 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 11 m/s, is brought to rest with constant acceleration in a distance of 43 m.

First I found the time it to to decelerate
D=(V+Vo)/2 T
gave me a value of .78seconds
plugged it into V=Vo+at
a=14.1m/s^2

F=ma
so the force is 1500Kg * (9.8+14.1) which is 35850
thats wrong, thanks in advance

 

[Doc Al]

First I found the time it to to decelerate
D=(V+Vo)/2 T
gave me a value of .78seconds

Redo this calculation.

 

[B-80]

thanks, stupid decimal.

 

[SolidTwinz]

How did you figure out the time?

 

[Doc Al]

How did you figure out the time?

Read the first post. (Distance = average speed X time)

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