What is the final velocity and angle of ball 2 after collision on a pool table?

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The discussion revolves around calculating the final velocity and angle of ball 2 after a collision on a pool table. Given the masses and initial velocities of both balls, the relevant conservation of momentum equation is applied. Ball 1 has a mass of 4 kg and an initial velocity of 8 m/s, while ball 2, with a mass of 10 kg, starts at rest. After the collision, ball 1 moves at 3 m/s, and ball 2 moves at a speed of 3 m/s at an angle of 34 degrees. The main confusion lies in determining the correct method to calculate ball 2's final velocity and angle after the collision.
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POOL TABLE PROBLEM.
When ball 1 hits ball 2, they both go off at different angles. What is the final velocity of the second ball?

GIVEN:
ball 1=4 kg
ball 2= 10 kg
Vo1=8 m/s
Vf1=3 m/s
Vo2=0
θ=34 ° (ball 2 moves at a speed of 3 m/s @ 34°)
Solve for Vf2 and the angle for ball 2 after the collision (Angle β)

Relevant equations:
m1vo1 + m2vo2 = m1vf1 + m2vf2

i did (4)(8) + 0 = (10)(vf2)

i had no clue if this was right though. are you supposed to use sin, cos, or tan θ?
 
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bmx_Freestyle said:
POOL TABLE PROBLEM.
When ball 1 hits ball 2, they both go off at different angles. What is the final velocity of the second ball?

GIVEN:
ball 1=4 kg
ball 2= 10 kg
Vo1=8 m/s
Vf1=3 m/s
Vo2=0
θ=34 ° (ball 2 moves at a speed of 3 m/s @ 34°)
Solve for Vf2 and the angle for ball 2 after the collision (Angle β)
But you just said that ball 2 moves at a speed of 3 m/s @ 34° :confused:
 
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