What is the final velocity of a dropped package in free fall?

AI Thread Summary
The problem involves a package dropped from a hot air balloon ascending at 10 m/s from a height of 61 m. The equations of motion are applied to determine the final velocity upon impact with the ground. The initial velocity is considered positive due to the balloon's upward motion, while gravitational acceleration is negative. A calculation using the equation v(final) = v(initial) + at suggests the final velocity is approximately 55.962 m/s, but there is confusion regarding the sign of the initial velocity. Clarification on the direction of velocities and acceleration is necessary for an accurate solution.
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Homework Statement



a hot air balloon is ascending at the rate of 10 m/s and is 61 m above the ground when a package is dropped over the side.

with what speed does it hit the ground

Homework Equations



y(final) - y(initial)= vt + .5at^2
v(final)=v(initial) + at

a= -g = 9.8 m/s
v(initial)= 10m/s
y(initial)=61m
y(final)=0m
v(final)=?
t=4.69 s and -2.65


The Attempt at a Solution



what i did was used the equation V(final)=V(inital) + at and plugged in the numbers

V(final)= 10m + 9.8(4.69) = 55.962

not sure what i am doing wrong. am i using the wrong initial velocity?
 
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The balloon is ascending so the initial velocity is upward, the final is downward. g is downward, the initial velocity and the acceleration have opposite signs.ehild
 
I think the sign of your initial velocity is wrong.
 
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