What is the force on an electron traveling parallel to the wire

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Homework Help Overview

The discussion revolves around calculating the magnetic field and the force on an electron in relation to current-carrying wires. The subject area includes electromagnetism, specifically the application of the Lorentz Force law and magnetic field calculations between parallel wires.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the magnetic field between two parallel wires and the application of the Lorentz Force law to determine the force on an electron. Questions arise regarding the correctness of the magnetic field calculations and the application of the right-hand rule for determining force direction.

Discussion Status

Some participants have shared their calculations and are seeking confirmation on their approaches. There is an ongoing exploration of the magnetic field's direction and the force on the electron, with some guidance provided regarding the interpretation of results.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a noted confusion regarding the right-hand rule and its application in this context.

stonnn
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1. Two parallel wires 0.200 m apart carry currents in opposite directions of 5.00 A. Find the
magnetic field between the wires 0.0500 m from one of them and 0.150 m from the other.

2. A long straight wire carries a current of 100. A.
a. What is the force on an electron traveling parallel to the wire, in the opposite
direction to the current, at a speed of 2.50x106 m/s when it is 0.100 m from the
wire?

Attempt: F=qvB

b. Find the force on the electron under the above circumstances when it is traveling
perpendicular to the wire.
electronic charge 1.602x10-19 C
 
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Just writing the Lorentz Force law isn't really an attempt.

How would you think to approach it?
 


for the first one, do we just get the magnetic field total? This is what i did.

Btotal = B1 + B2
B1 = MoI/2IIr ---> [(1.26X10^-6)(5)/(6.28)(15)
B2 = MoI/2IIr ---> [(1.26x10^-6)(5)/(6.28)(0.05)

Is that right?

for the second one, I calculated magnetic field first. Then, used this equation:

F=qvb
Magnetic force faces the positive x direction, right? I am still kinda confused about the right hand rule

b. Magnetic force faces in the negative y direction?

please let me know if I am wrong about anything. Thanks !
 

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