What is the formula for calculating average power of electromagnetic waves?

Click For Summary
SUMMARY

The formula for calculating the average power of electromagnetic waves is given by Savg = Em * Bm / (2*μ0 * c). In this equation, Savg represents the average power, Em is the maximum electric field strength, and Bm is the maximum magnetic field strength. The calculation focuses solely on the maximum values of the electric and magnetic fields, making the result independent of frequency or position. This approach simplifies the analysis of electromagnetic wave power without the need to consider the cosine function.

PREREQUISITES
  • Understanding of electromagnetic wave properties
  • Familiarity with the Poynting vector concept
  • Knowledge of the constants μ0 (permeability of free space) and c (speed of light)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of the Poynting vector
  • Learn about the significance of maximum field values in electromagnetic theory
  • Explore the relationship between electric and magnetic fields in wave propagation
  • Investigate applications of electromagnetic wave power calculations in engineering
USEFUL FOR

Students studying electromagnetism, physics educators, and engineers working with electromagnetic wave applications will benefit from this discussion.

blackbyron
Messages
47
Reaction score
0

Homework Statement



son01s.jpg


Homework Equations


Savg = Em * Bm / (2*μ0 * c)


The Attempt at a Solution


I solved for S avg without calculating inside the cos, but I got it right.

The z and t is given, but is there the reason why you don't solve inside the cos, or is it the bug? it's makes me confused.

Thanks
 
Physics news on Phys.org
Savg = Em * Bm / (2*μ0 * c)

What do Savg, Em and Bm mean?

ehild
 
I see, I look at my teacher's notes and saw the exact equation.

So to solve for Savg, it only cares about the maximum values right?
 
Right, the result is independent of frequency or position.
 
Thanks for your help.
 

Thread 'Magnitude of buoyant force in fluids of different densities'

The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?
View full post »

Similar threads

Problem about electromagnetic waves -- Writing equations for B(t) and E(t)
  • · Replies 2 ·
Replies
2
Views
1K
Superposition of Plane EM Waves Using Complex Notation
  • · Replies 2 ·
Replies
2
Views
1K
Superposition of two one-dimensional harmonic waves
  • · Replies 10 ·
Replies
10
Views
2K
An Electromagnetic wave goes from air into a medium....
  • · Replies 3 ·
Replies
3
Views
3K
EM Waves - Would the bulb glow?
  • · Replies 8 ·
Replies
8
Views
5K
Power calculations of AC signal
  • · Replies 1 ·
Replies
1
Views
2K
How to determine the direction of the E-field of an EM wave
  • · Replies 7 ·
Replies
7
Views
2K
Electromagnetic waves radiating away from a transmitting tower
  • · Replies 3 ·
Replies
3
Views
2K
What is the Energy Transmitted by a Plane EM Wave Passing Through a Window?
  • · Replies 2 ·
Replies
2
Views
2K
How Does Permittivity Affect Energy Transmission in EM Waves?
  • · Replies 3 ·
Replies
3
Views
1K