What is the formula for calculating force using a spring balance?

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SUMMARY

The formula for calculating force using a spring balance involves understanding the tension in the strings connected to two masses, m1 and m2. The correct approach is to analyze the forces acting on each mass and apply Newton's second law, resulting in the equations T1 = m1(g - a) and T2 = m2(g + a). The spring balance measures the tension, which can be expressed as T = 2m1m2/(m1 + m2) when both masses are equal. This discussion emphasizes the importance of free body diagrams and the static versus dynamic conditions of the system.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of free body diagrams
  • Familiarity with tension in strings and pulleys
  • Basic algebra for solving equations
NEXT STEPS
  • Study the principles of static and dynamic equilibrium in physics
  • Learn how to draw and analyze free body diagrams
  • Explore the concept of tension in systems with multiple masses
  • Review Newton's second law and its applications in real-world scenarios
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of force measurement using spring balances.

  • #31
Suyash Singh said:
i don't know the math here but in this case one of the force acts as a "support" ,that is, we could replace one of the force with a wall.

what i mean to say is that two teams pulling rope from two sides with same force
is the same case as
a team pulling a rope attached to a stationary wall with the same force.
but i don't know the math because its not given properly anywhere.
 
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  • #32
Suyash Singh said:
Applying on m2
force=m2(g+a)
Applying on m1
force=m1(g-a)
Right. You have two equations and two unknowns. Solve to find the force.
How does that force relate to what the spring balance shows?
 
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  • #33
haruspex said:
Right. You have two equations and two unknowns. Solve to find the force.
How does that force relate to what the spring balance shows?
a=(m1-m2)g/m1+m2
force=2m1m2/m1+m2
oh so the spring balance shows 2m1m2/m1+m2 since it divides the tension produced by g to get the mass
 
  • #34
and
Suyash Singh said:
a=(m1-m2)g/m1+m2
force=2m1m2/m1+m2
oh so the spring balance shows 2m1m2/m1+m2 since it divides the tension produced by g to get the mass
that's why two teams pulling a rope with the same force of 1000N will produce a tension of 1000N !

because tension=2*1000*1000/(1000+1000)=1000N
wow now i am so clear about this :)
 
  • #35
Suyash Singh said:
force=2m1m2/m1+m2
You missed out g and you should use parentheses in the denominator, but other than that, yes.
 
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