What is the formula for calculating force using a spring balance?

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Suyash Singh said:
i don't know the math here but in this case one of the force acts as a "support" ,that is, we could replace one of the force with a wall.

what i mean to say is that two teams pulling rope from two sides with same force
is the same case as
a team pulling a rope attached to a stationary wall with the same force.
but i don't know the math because its not given properly anywhere.
 
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Suyash Singh said:
Applying on m2
force=m2(g+a)
Applying on m1
force=m1(g-a)
Right. You have two equations and two unknowns. Solve to find the force.
How does that force relate to what the spring balance shows?
 
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haruspex said:
Right. You have two equations and two unknowns. Solve to find the force.
How does that force relate to what the spring balance shows?
a=(m1-m2)g/m1+m2
force=2m1m2/m1+m2
oh so the spring balance shows 2m1m2/m1+m2 since it divides the tension produced by g to get the mass
 
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Suyash Singh said:
a=(m1-m2)g/m1+m2
force=2m1m2/m1+m2
oh so the spring balance shows 2m1m2/m1+m2 since it divides the tension produced by g to get the mass
that's why two teams pulling a rope with the same force of 1000N will produce a tension of 1000N !

because tension=2*1000*1000/(1000+1000)=1000N
wow now i am so clear about this :)