What is the frequency range of ultraviolet radiation?

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Homework Help Overview

The discussion revolves around the frequency range of ultraviolet radiation, which is part of the electromagnetic spectrum with specific wavelength limits. The original poster attempts to calculate the frequency range based on given wavelength values and the speed of light.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster presents calculations using the relationship between speed, frequency, and wavelength. Some participants question the interpretation of "range" and suggest clarifying the presentation of results.

Discussion Status

Participants are engaging with the calculations provided, with some confirming the correctness of the original poster's approach. There is an exploration of how to express the frequency range, indicating a productive dialogue without explicit consensus.

Contextual Notes

There is an implicit assumption about the definitions of frequency and wavelength, as well as the need for clarity in presenting the range of values derived from calculations.

wilson_chem90
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Ultraviolet radiation is part of the electromagnetic spectrum that has wavelengths in the range of 200 nm to 400 nm. Given that the speed of all forms of electromagnetic radiation is 3.0 x 10^8 m/s, calculate the frequency range of ultraviolet radiation.



Relevant equations:
V = f(wavelength)

vshallow/(wavelength) shallow = vdeep/(wavelength) deep



The attempt at a solution:

vshallow/(wavelength)shallow = vdeep/(wavelength)deep

(3.0 x 10^8 m/s) / (4.0 x 10^-7m) = (3.0 x 10^8 m/s) / (2.0 x 10^-7m)

(7.5 x 10^14 Hz) = (1.5 x 10^15 Hz)

f = f2 - f1
= (1.5 x 10^15 Hz) - (7.5 x 10^14 Hz)
= 7.5 x 10^14 Hz

I'm not sure if this is correct, but can someone please confirm? thanks
 
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Hi wilson_chem90! :smile:

(try using the X2 tag just above the Reply box :wink:)

Yes, your calculations are fine :smile:

(but I wonder whether by "range" they just want you to say "the range is from 7.5 x 1014 Hz to 1.5 x 1015 Hz" ?)
 
thank you very much, i never thought of that. it makes more sense. I'll just put both answers just in case. Thank you!
 
actually the way i answered would probably be the net frequency, so yours makes a lot more sense.
 
:wink: goldfishsense! :biggrin:
 

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