Loren Booda Messages 3,115 Reaction score 4 Thread starter Feb 2, 2012 #1 What is the g-force on a car, initially traveling at 55 mph, when stopping across the diameter of a dime?
What is the g-force on a car, initially traveling at 55 mph, when stopping across the diameter of a dime?
Pythagorean Science Advisor Messages 4,430 Reaction score 327 Feb 3, 2012 #2 convert mph to mps, find the acceleration from change in velocity, multiply by mass, divide by g.
Pythagorean Science Advisor Messages 4,430 Reaction score 327 Feb 3, 2012 #3 Find acceleration from change in velocity over given distance, that is.
KingNothing Messages 880 Reaction score 4 Feb 3, 2012 #4 Would it not be appropriate to solve a system of equations, d=1/2 * a * t^2, d = 17.91 mm, and a * t = 55 mph? Doing this I get about 16.9 kilometers / s^2, or 1721g. Last edited: Feb 3, 2012
Would it not be appropriate to solve a system of equations, d=1/2 * a * t^2, d = 17.91 mm, and a * t = 55 mph? Doing this I get about 16.9 kilometers / s^2, or 1721g.
Pythagorean Science Advisor Messages 4,430 Reaction score 327 Feb 3, 2012 #5 [tex]a = \frac{v^2 - v_0^2}{2d}[/tex] but [tex]v_0 = 0[/tex] (in my ref frame : ) so [tex]a = \frac{v^2}{2d}[/tex] Of course, this assume constant acceleration...
[tex]a = \frac{v^2 - v_0^2}{2d}[/tex] but [tex]v_0 = 0[/tex] (in my ref frame : ) so [tex]a = \frac{v^2}{2d}[/tex] Of course, this assume constant acceleration...