What is the general solution for dy/dx=lnx/(xy+xy^3)?

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SUMMARY

The general solution for the differential equation dy/dx = lnx/(xy + xy^3) can be derived by rearranging the equation to (y + y^3)dy = (lnx/x)dx. Upon integration, the correct approach leads to the conclusion that the solution involves the expression 2(lnx)^2 = 2y^2 + y^4. A critical error noted in the discussion is the misinterpretation of the integration process, particularly when substituting t = lnx, which simplifies the integration to dt/t, yielding ln(t) instead of (lnx)^2.

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Homework Statement


Find the general solution of: dy/dx=lnx/(xy+xy^3)


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The Attempt at a Solution


In order to find the general solution, i rerrange the equation to:(y+y^3)dy=(lnx/x)dx,
then int(y+y^3)dy=int(lnx/x)dx, then i got 2(lnx)^2=2y^2+y^4. then i rerange y to the LHS and x to the RHS, but the answer looks strange.
Can anyone find where i did wrong?
 
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If you have t=ln(x), then dt=dx/x, so you are integrating dt/t, giving lnt.

So your final answer would not be (lnx)^2.
 

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