What is the gradient of a divergence and is it always zero?

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Discussion Overview

The discussion centers around the concept of the gradient of a divergence in vector calculus, specifically whether it is always equal to the zero vector. Participants explore related vector identities and their implications in the context of electromagnetic theory.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant inquires about the gradient of a divergence and whether it is always zero, indicating a need for clarification on vector calculus concepts.
  • Another participant provides links to discussions and examples related to the topic, suggesting that these resources may help in understanding the gradient of divergence.
  • A later reply highlights a vector identity relevant to the discussion, noting that while in specific cases (like in vacuum electromagnetic fields) the divergence may be zero, this is not universally applicable, as the first term in the identity is not always zero.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether the gradient of a divergence is always zero, and multiple viewpoints regarding the implications of vector identities are presented.

Contextual Notes

The discussion does not resolve the conditions under which the gradient of a divergence may or may not be zero, nor does it clarify the assumptions underlying the vector identities mentioned.

James Essig
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Hi Folks,

Was just curious as to what is the gradient of a divergence is and is it always equal to the zero vector. I am doing some free lance research and find that I need to refresh my knowledge of vector calculus a bit. I am having some difficulty with finding web-based sources for the gradient of a divergence.
 
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Thanks for the info fresh_42. I found those two links very helpful and I solved my problem of the reason for my inquiry.
 
One very important vector identity, (it is used in showing Maxwell's equations result in an electromagnetic wave equation), is ## \nabla \times \nabla \times \vec{A}=\nabla (\nabla \cdot \vec{A})-\nabla^2 \vec{A} ##. For the case that is often shown to demonstrate the wave equation in a vacuum, ## \nabla \cdot \vec{E}=0 ##, but in general, the first term on the right side of the vector identity equation is not equal to zero.
 

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