What is the gravitational Field?

AI Thread Summary
The discussion centers on calculating the gravitational field at a point inside a thin spherical shell with a radius of 3.4 m and a mass of 456 kg. Utilizing the shell theorem, it is established that the gravitational field inside a symmetrical shell is zero. Participants attempted to apply gravitational equations but concluded that the gravitational field 1.4 m from the center is indeed zero. The conversation also includes a light-hearted suggestion to prepare for class by reviewing upcoming problems. Understanding the shell theorem is emphasized as crucial for solving such gravitational queries.
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Hint: Use shell theorem and/or flux argument for a symmetrical shell.

A thin spherical shell has a radius of 3.4 m and a mass of 456 kg. The Universal gravitational constant is 6.6726 x 10^-11 N m^2/kg^2.

What is the gravitational field 1.4 m from the center of the shell? Answers in units of N/kg.

Attempt--
I tried this equations, a= - G(delta m)/ (x^2 + y^2)
 
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forget equations. picture the flux
 
grouchy said:
Hint: Use shell theorem and/or flux argument for a symmetrical shell.

A thin spherical shell has a radius of 3.4 m and a mass of 456 kg. The Universal gravitational constant is 6.6726 x 10^-11 N m^2/kg^2.

What is the gravitational field 1.4 m from the center of the shell? Answers in units of N/kg.

Attempt--
I tried this equations, a= - G(delta m)/ (x^2 + y^2)

The gravitational field is a vector field. The gravity at the center will be the integral of all the mass of the shell acting at that point through all directions.

Maybe read up a little about the Shell Theorem?
http://en.wikipedia.org/wiki/Shell_theorem
 
wait..is the answer zero?
 
yip.
 
eh.. thanks lol! Need to pay attention in class a bit more :)
 
grouchy said:
wait..is the answer zero?

Correctamundo.

Good luck.

Study Tip: Read next week's problems before going to next week's class. Then you know what part of the lecture to snooze through.
 
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